3(n-5)=27

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Solution for 3(n-5)=27 equation:



3(n-5)=27
We move all terms to the left:
3(n-5)-(27)=0
We multiply parentheses
3n-15-27=0
We add all the numbers together, and all the variables
3n-42=0
We move all terms containing n to the left, all other terms to the right
3n=42
n=42/3
n=14

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