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3(n-6)+5=2(n-5)+n-2
We move all terms to the left:
3(n-6)+5-(2(n-5)+n-2)=0
We multiply parentheses
3n-(2(n-5)+n-2)-18+5=0
We calculate terms in parentheses: -(2(n-5)+n-2), so:We add all the numbers together, and all the variables
2(n-5)+n-2
We add all the numbers together, and all the variables
n+2(n-5)-2
We multiply parentheses
n+2n-10-2
We add all the numbers together, and all the variables
3n-12
Back to the equation:
-(3n-12)
3n-(3n-12)-13=0
We get rid of parentheses
3n-3n+12-13=0
We add all the numbers together, and all the variables
-1!=0
There is no solution for this equation
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