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3(n-6)+9(n+5)=1-n+10n-4
We move all terms to the left:
3(n-6)+9(n+5)-(1-n+10n-4)=0
We add all the numbers together, and all the variables
3(n-6)+9(n+5)-(9n-3)=0
We multiply parentheses
3n+9n-(9n-3)-18+45=0
We get rid of parentheses
3n+9n-9n+3-18+45=0
We add all the numbers together, and all the variables
3n+30=0
We move all terms containing n to the left, all other terms to the right
3n=-30
n=-30/3
n=-10
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