3(n-6)=-21+4n

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Solution for 3(n-6)=-21+4n equation: 



3(n-6)=-21+4n

We move all terms to the left:

3(n-6)-(-21+4n)=0

We add all the numbers together, and all the variables

3(n-6)-(4n-21)=0

We multiply parentheses

3n-(4n-21)-18=0

We get rid of parentheses

3n-4n+21-18=0

We add all the numbers together, and all the variables

-1n+3=0

We move all terms containing n to the left, all other terms to the right

-n=-3

n=-3/-1

n=+3

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