3(n-8)+4n+3=7(n-3)

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Solution for 3(n-8)+4n+3=7(n-3) equation: 



3(n-8)+4n+3=7(n-3)

We move all terms to the left:

3(n-8)+4n+3-(7(n-3))=0

We add all the numbers together, and all the variables

4n+3(n-8)-(7(n-3))+3=0

We multiply parentheses

4n+3n-(7(n-3))-24+3=0



We calculate terms in parentheses: -(7(n-3)), so:

7(n-3)

We multiply parentheses

7n-21

Back to the equation:

-(7n-21)



We add all the numbers together, and all the variables

7n-(7n-21)-21=0

We get rid of parentheses

7n-7n+21-21=0

We add all the numbers together, and all the variables

=0

n=0/1

n=0

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