3(n-8)+6(n-19)=6

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Solution for 3(n-8)+6(n-19)=6 equation: 



3(n-8)+6(n-19)=6

We move all terms to the left:

3(n-8)+6(n-19)-(6)=0

We multiply parentheses

3n+6n-24-114-6=0

We add all the numbers together, and all the variables

9n-144=0

We move all terms containing n to the left, all other terms to the right

9n=144

n=144/9

n=16

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