3(n/1)-2=4(2n+3)

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Solution for 3(n/1)-2=4(2n+3) equation: 


n in (-oo:+oo)

3*(n/1)-2 = 4*(2*n+3) // - 4*(2*n+3)

3*(n/1)-(4*(2*n+3))-2 = 0

3*n-4*(2*n+3)-2 = 0

3*n-4*(2*n+3)-2 = 0

-5*n-12-2 = 0

-5*n-14 = 0

-5*n-14 = 0

-5*n-14 = 0 // + 14

-5*n = 14 // : -5

n = 14/(-5)

n = -14/5

n = -14/5

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