3(p+2)-8=2(p-6)+p+10

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Solution for 3(p+2)-8=2(p-6)+p+10 equation:



3(p+2)-8=2(p-6)+p+10
We move all terms to the left:
3(p+2)-8-(2(p-6)+p+10)=0
We multiply parentheses
3p-(2(p-6)+p+10)+6-8=0
We calculate terms in parentheses: -(2(p-6)+p+10), so:
2(p-6)+p+10
We add all the numbers together, and all the variables
p+2(p-6)+10
We multiply parentheses
p+2p-12+10
We add all the numbers together, and all the variables
3p-2
Back to the equation:
-(3p-2)
We add all the numbers together, and all the variables
3p-(3p-2)-2=0
We get rid of parentheses
3p-3p+2-2=0
We add all the numbers together, and all the variables
=0
p=0/1
p=0

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