3(p+2)=(2p+4)+9

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Solution for 3(p+2)=(2p+4)+9 equation: 



3(p+2)=(2p+4)+9

We move all terms to the left:

3(p+2)-((2p+4)+9)=0

We multiply parentheses

3p-((2p+4)+9)+6=0



We calculate terms in parentheses: -((2p+4)+9), so:

(2p+4)+9

We get rid of parentheses

2p+4+9

We add all the numbers together, and all the variables

2p+13

Back to the equation:

-(2p+13)



We get rid of parentheses

3p-2p-13+6=0

We add all the numbers together, and all the variables

p-7=0

We move all terms containing p to the left, all other terms to the right

p=7

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