3(p+2)=2(p-3)+8

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Solution for 3(p+2)=2(p-3)+8 equation: 



3(p+2)=2(p-3)+8

We move all terms to the left:

3(p+2)-(2(p-3)+8)=0

We multiply parentheses

3p-(2(p-3)+8)+6=0



We calculate terms in parentheses: -(2(p-3)+8), so:

2(p-3)+8

We multiply parentheses

2p-6+8

We add all the numbers together, and all the variables

2p+2

Back to the equation:

-(2p+2)



We get rid of parentheses

3p-2p-2+6=0

We add all the numbers together, and all the variables

p+4=0

We move all terms containing p to the left, all other terms to the right

p=-4

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