3(p+2)=3(2p-4)=19

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Solution for 3(p+2)=3(2p-4)=19 equation: 



3(p+2)=3(2p-4)=19

We move all terms to the left:

3(p+2)-(3(2p-4))=0

We multiply parentheses

3p-(3(2p-4))+6=0



We calculate terms in parentheses: -(3(2p-4)), so:

3(2p-4)

We multiply parentheses

6p-12

Back to the equation:

-(6p-12)



We get rid of parentheses

3p-6p+12+6=0

We add all the numbers together, and all the variables

-3p+18=0

We move all terms containing p to the left, all other terms to the right

-3p=-18

p=-18/-3

p=+6

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