3(p+2)=3(p-4)+7

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Solution for 3(p+2)=3(p-4)+7 equation: 



3(p+2)=3(p-4)+7

We move all terms to the left:

3(p+2)-(3(p-4)+7)=0

We multiply parentheses

3p-(3(p-4)+7)+6=0



We calculate terms in parentheses: -(3(p-4)+7), so:

3(p-4)+7

We multiply parentheses

3p-12+7

We add all the numbers together, and all the variables

3p-5

Back to the equation:

-(3p-5)



We get rid of parentheses

3p-3p+5+6=0

We add all the numbers together, and all the variables

11!=0

There is no solution for this equation

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