3(p+4)=2(p-6)+p+24

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Solution for 3(p+4)=2(p-6)+p+24 equation: 



3(p+4)=2(p-6)+p+24

We move all terms to the left:

3(p+4)-(2(p-6)+p+24)=0

We multiply parentheses

3p-(2(p-6)+p+24)+12=0



We calculate terms in parentheses: -(2(p-6)+p+24), so:

2(p-6)+p+24

We add all the numbers together, and all the variables

p+2(p-6)+24

We multiply parentheses

p+2p-12+24

We add all the numbers together, and all the variables

3p+12

Back to the equation:

-(3p+12)



We get rid of parentheses

3p-3p-12+12=0

We add all the numbers together, and all the variables

=0

p=0/1

p=0

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