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3(p+5)=2(p-3)+p+21
We move all terms to the left:
3(p+5)-(2(p-3)+p+21)=0
We multiply parentheses
3p-(2(p-3)+p+21)+15=0
We calculate terms in parentheses: -(2(p-3)+p+21), so:We get rid of parentheses
2(p-3)+p+21
We add all the numbers together, and all the variables
p+2(p-3)+21
We multiply parentheses
p+2p-6+21
We add all the numbers together, and all the variables
3p+15
Back to the equation:
-(3p+15)
3p-3p-15+15=0
We add all the numbers together, and all the variables
=0
p=0/1
p=0
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