3(p+5)=2(p-6)+p+27

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Solution for 3(p+5)=2(p-6)+p+27 equation: 


Simplifying
3(p + 5) = 2(p + -6) + p + 27

Reorder the terms:
3(5 + p) = 2(p + -6) + p + 27
(5 * 3 + p * 3) = 2(p + -6) + p + 27
(15 + 3p) = 2(p + -6) + p + 27

Reorder the terms:
15 + 3p = 2(-6 + p) + p + 27
15 + 3p = (-6 * 2 + p * 2) + p + 27
15 + 3p = (-12 + 2p) + p + 27

Reorder the terms:
15 + 3p = -12 + 27 + 2p + p

Combine like terms: -12 + 27 = 15
15 + 3p = 15 + 2p + p

Combine like terms: 2p + p = 3p
15 + 3p = 15 + 3p

Add '-15' to each side of the equation.
15 + -15 + 3p = 15 + -15 + 3p

Combine like terms: 15 + -15 = 0
0 + 3p = 15 + -15 + 3p
3p = 15 + -15 + 3p

Combine like terms: 15 + -15 = 0
3p = 0 + 3p
3p = 3p

Add '-3p' to each side of the equation.
3p + -3p = 3p + -3p

Combine like terms: 3p + -3p = 0
0 = 3p + -3p

Combine like terms: 3p + -3p = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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