3(p+6)=2(p-5)+p+28

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Solution for 3(p+6)=2(p-5)+p+28 equation: 


Simplifying
3(p + 6) = 2(p + -5) + p + 28

Reorder the terms:
3(6 + p) = 2(p + -5) + p + 28
(6 * 3 + p * 3) = 2(p + -5) + p + 28
(18 + 3p) = 2(p + -5) + p + 28

Reorder the terms:
18 + 3p = 2(-5 + p) + p + 28
18 + 3p = (-5 * 2 + p * 2) + p + 28
18 + 3p = (-10 + 2p) + p + 28

Reorder the terms:
18 + 3p = -10 + 28 + 2p + p

Combine like terms: -10 + 28 = 18
18 + 3p = 18 + 2p + p

Combine like terms: 2p + p = 3p
18 + 3p = 18 + 3p

Add '-18' to each side of the equation.
18 + -18 + 3p = 18 + -18 + 3p

Combine like terms: 18 + -18 = 0
0 + 3p = 18 + -18 + 3p
3p = 18 + -18 + 3p

Combine like terms: 18 + -18 = 0
3p = 0 + 3p
3p = 3p

Add '-3p' to each side of the equation.
3p + -3p = 3p + -3p

Combine like terms: 3p + -3p = 0
0 = 3p + -3p

Combine like terms: 3p + -3p = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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