3(p-2)+p=6(p+3)-4p

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Solution for 3(p-2)+p=6(p+3)-4p equation: 



3(p-2)+p=6(p+3)-4p

We move all terms to the left:

3(p-2)+p-(6(p+3)-4p)=0

We add all the numbers together, and all the variables

p+3(p-2)-(6(p+3)-4p)=0

We multiply parentheses

p+3p-(6(p+3)-4p)-6=0



We calculate terms in parentheses: -(6(p+3)-4p), so:

6(p+3)-4p

We add all the numbers together, and all the variables

-4p+6(p+3)

We multiply parentheses

-4p+6p+18

We add all the numbers together, and all the variables

2p+18

Back to the equation:

-(2p+18)



We add all the numbers together, and all the variables

4p-(2p+18)-6=0

We get rid of parentheses

4p-2p-18-6=0

We add all the numbers together, and all the variables

2p-24=0

We move all terms containing p to the left, all other terms to the right

2p=24

p=24/2

p=12

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