3(p-4)+6(p+3)=3(3p+2)

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Solution for 3(p-4)+6(p+3)=3(3p+2) equation: 



3(p-4)+6(p+3)=3(3p+2)

We move all terms to the left:

3(p-4)+6(p+3)-(3(3p+2))=0

We multiply parentheses

3p+6p-(3(3p+2))-12+18=0



We calculate terms in parentheses: -(3(3p+2)), so:

3(3p+2)

We multiply parentheses

9p+6

Back to the equation:

-(9p+6)



We add all the numbers together, and all the variables

9p-(9p+6)+6=0

We get rid of parentheses

9p-9p-6+6=0

We add all the numbers together, and all the variables

=0

p=0/1

p=0

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