3(p-5)=7(p-1)

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Solution for 3(p-5)=7(p-1) equation: 



3(p-5)=7(p-1)

We move all terms to the left:

3(p-5)-(7(p-1))=0

We multiply parentheses

3p-(7(p-1))-15=0



We calculate terms in parentheses: -(7(p-1)), so:

7(p-1)

We multiply parentheses

7p-7

Back to the equation:

-(7p-7)



We get rid of parentheses

3p-7p+7-15=0

We add all the numbers together, and all the variables

-4p-8=0

We move all terms containing p to the left, all other terms to the right

-4p=8

p=8/-4

p=-2

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