3(p-6)+1=9p-8

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Solution for 3(p-6)+1=9p-8 equation: 



3(p-6)+1=9p-8

We move all terms to the left:

3(p-6)+1-(9p-8)=0

We multiply parentheses

3p-(9p-8)-18+1=0

We get rid of parentheses

3p-9p+8-18+1=0

We add all the numbers together, and all the variables

-6p-9=0

We move all terms containing p to the left, all other terms to the right

-6p=9

p=9/-6

p=-1+1/2

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