3(p-7)-(p-4)=12

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Solution for 3(p-7)-(p-4)=12 equation: 



3(p-7)-(p-4)=12

We move all terms to the left:

3(p-7)-(p-4)-(12)=0

We multiply parentheses

3p-(p-4)-21-12=0

We get rid of parentheses

3p-p+4-21-12=0

We add all the numbers together, and all the variables

2p-29=0

We move all terms containing p to the left, all other terms to the right

2p=29

p=29/2

p=14+1/2

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