3(q+1)+4=19

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Solution for 3(q+1)+4=19 equation: 



3(q+1)+4=19

We move all terms to the left:

3(q+1)+4-(19)=0

We add all the numbers together, and all the variables

3(q+1)-15=0

We multiply parentheses

3q+3-15=0

We add all the numbers together, and all the variables

3q-12=0

We move all terms containing q to the left, all other terms to the right

3q=12

q=12/3

q=4

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