3(q+2)+4q=-36

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Solution for 3(q+2)+4q=-36 equation: 



3(q+2)+4q=-36

We move all terms to the left:

3(q+2)+4q-(-36)=0

We add all the numbers together, and all the variables

4q+3(q+2)+36=0

We multiply parentheses

4q+3q+6+36=0

We add all the numbers together, and all the variables

7q+42=0

We move all terms containing q to the left, all other terms to the right

7q=-42

q=-42/7

q=-6

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