3(q+4/3)=12

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Solution for 3(q+4/3)=12 equation:



3(q+4/3)=12
We move all terms to the left:
3(q+4/3)-(12)=0
We add all the numbers together, and all the variables
3(+q+4/3)-12=0
We multiply parentheses
3q-12+4/3*3=0
We multiply all the terms by the denominator
3q*3*3+4-12*3*3=0
We add all the numbers together, and all the variables
3q*3*3-104=0
Wy multiply elements
27q*3-104=0
Wy multiply elements
81q-104=0
We move all terms containing q to the left, all other terms to the right
81q=104
q=104/81
q=1+23/81

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