3(q-1)+7=3q+4

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Solution for 3(q-1)+7=3q+4 equation: 


Simplifying
3(q + -1) + 7 = 3q + 4

Reorder the terms:
3(-1 + q) + 7 = 3q + 4
(-1 * 3 + q * 3) + 7 = 3q + 4
(-3 + 3q) + 7 = 3q + 4

Reorder the terms:
-3 + 7 + 3q = 3q + 4

Combine like terms: -3 + 7 = 4
4 + 3q = 3q + 4

Reorder the terms:
4 + 3q = 4 + 3q

Add '-4' to each side of the equation.
4 + -4 + 3q = 4 + -4 + 3q

Combine like terms: 4 + -4 = 0
0 + 3q = 4 + -4 + 3q
3q = 4 + -4 + 3q

Combine like terms: 4 + -4 = 0
3q = 0 + 3q
3q = 3q

Add '-3q' to each side of the equation.
3q + -3q = 3q + -3q

Combine like terms: 3q + -3q = 0
0 = 3q + -3q

Combine like terms: 3q + -3q = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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