3(q-1)=2(q+1)

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Solution for 3(q-1)=2(q+1) equation: 



3(q-1)=2(q+1)

We move all terms to the left:

3(q-1)-(2(q+1))=0

We multiply parentheses

3q-(2(q+1))-3=0



We calculate terms in parentheses: -(2(q+1)), so:

2(q+1)

We multiply parentheses

2q+2

Back to the equation:

-(2q+2)



We get rid of parentheses

3q-2q-2-3=0

We add all the numbers together, and all the variables

q-5=0

We move all terms containing q to the left, all other terms to the right

q=5

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