3(q-10)+4(q-18)=10

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Solution for 3(q-10)+4(q-18)=10 equation: 


Simplifying
3(q + -10) + 4(q + -18) = 10

Reorder the terms:
3(-10 + q) + 4(q + -18) = 10
(-10 * 3 + q * 3) + 4(q + -18) = 10
(-30 + 3q) + 4(q + -18) = 10

Reorder the terms:
-30 + 3q + 4(-18 + q) = 10
-30 + 3q + (-18 * 4 + q * 4) = 10
-30 + 3q + (-72 + 4q) = 10

Reorder the terms:
-30 + -72 + 3q + 4q = 10

Combine like terms: -30 + -72 = -102
-102 + 3q + 4q = 10

Combine like terms: 3q + 4q = 7q
-102 + 7q = 10

Solving
-102 + 7q = 10

Solving for variable 'q'.

Move all terms containing q to the left, all other terms to the right.

Add '102' to each side of the equation.
-102 + 102 + 7q = 10 + 102

Combine like terms: -102 + 102 = 0
0 + 7q = 10 + 102
7q = 10 + 102

Combine like terms: 10 + 102 = 112
7q = 112

Divide each side by '7'.
q = 16

Simplifying
q = 16

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