3(q-2)=2(q+1)-3

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Solution for 3(q-2)=2(q+1)-3 equation: 



3(q-2)=2(q+1)-3

We move all terms to the left:

3(q-2)-(2(q+1)-3)=0

We multiply parentheses

3q-(2(q+1)-3)-6=0



We calculate terms in parentheses: -(2(q+1)-3), so:

2(q+1)-3

We multiply parentheses

2q+2-3

We add all the numbers together, and all the variables

2q-1

Back to the equation:

-(2q-1)



We get rid of parentheses

3q-2q+1-6=0

We add all the numbers together, and all the variables

q-5=0

We move all terms containing q to the left, all other terms to the right

q=5

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