3(q-4)+16=3(q-2)-10

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Solution for 3(q-4)+16=3(q-2)-10 equation: 



3(q-4)+16=3(q-2)-10

We move all terms to the left:

3(q-4)+16-(3(q-2)-10)=0

We multiply parentheses

3q-(3(q-2)-10)-12+16=0



We calculate terms in parentheses: -(3(q-2)-10), so:

3(q-2)-10

We multiply parentheses

3q-6-10

We add all the numbers together, and all the variables

3q-16

Back to the equation:

-(3q-16)



We add all the numbers together, and all the variables

3q-(3q-16)+4=0

We get rid of parentheses

3q-3q+16+4=0

We add all the numbers together, and all the variables

20!=0

There is no solution for this equation

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