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3(q-5)+-6=3
We move all terms to the left:
3(q-5)+-6-(3)=0
determiningTheFunctionDomain 3(q-5)-6-3+=0
We add all the numbers together, and all the variables
3(q-5)=0
We multiply parentheses
3q-15=0
We move all terms containing q to the left, all other terms to the right
3q=15
q=15/3
q=5
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