3(q-5)=-3(2q-1)

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Solution for 3(q-5)=-3(2q-1) equation: 



3(q-5)=-3(2q-1)

We move all terms to the left:

3(q-5)-(-3(2q-1))=0

We multiply parentheses

3q-(-3(2q-1))-15=0



We calculate terms in parentheses: -(-3(2q-1)), so:

-3(2q-1)

We multiply parentheses

-6q+3

Back to the equation:

-(-6q+3)



We get rid of parentheses

3q+6q-3-15=0

We add all the numbers together, and all the variables

9q-18=0

We move all terms containing q to the left, all other terms to the right

9q=18

q=18/9

q=2

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