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3(q-5)=2(q+5)=
We move all terms to the left:
3(q-5)-(2(q+5))=0
We multiply parentheses
3q-(2(q+5))-15=0
We calculate terms in parentheses: -(2(q+5)), so:We get rid of parentheses
2(q+5)
We multiply parentheses
2q+10
Back to the equation:
-(2q+10)
3q-2q-10-15=0
We add all the numbers together, and all the variables
q-25=0
We move all terms containing q to the left, all other terms to the right
q=25
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