3(q-7)=27/3

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Solution for 3(q-7)=27/3 equation: 



3(q-7)=27/3

We move all terms to the left:

3(q-7)-(27/3)=0

We add all the numbers together, and all the variables

3(q-7)-9=0

We multiply parentheses

3q-21-9=0

We add all the numbers together, and all the variables

3q-30=0

We move all terms containing q to the left, all other terms to the right

3q=30

q=30/3

q=10

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