3(q-7)=27q=

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Solution for 3(q-7)=27q= equation: 



3(q-7)=27q=

We move all terms to the left:

3(q-7)-(27q)=0

We add all the numbers together, and all the variables

-27q+3(q-7)=0

We multiply parentheses

-27q+3q-21=0

We add all the numbers together, and all the variables

-24q-21=0

We move all terms containing q to the left, all other terms to the right

-24q=21

q=21/-24

q=-7/8

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