3(r+1)-(2(-2r)-3(3-r))=2(r+5)-4

Solution for 3(r+1)-(2(-2r)-3(3-r))=2(r+5)-4 equation:

3(r+1)-(2(-2r)-3(3-r))=2(r+5)-4

We move all terms to the left:

3(r+1)-(2(-2r)-3(3-r))-(2(r+5)-4)=0

We add all the numbers together, and all the variables

3(r+1)-(2(-2r)-3(-1r+3))-(2(r+5)-4)=0

We multiply parentheses

3r-(2(-2r)-3(-1r+3))-(2(r+5)-4)+3=0


We calculate terms in parentheses: -(2(-2r)-3(-1r+3)), so:

2(-2r)-3(-1r+3)

We multiply parentheses

-4r+3r-9

We add all the numbers together, and all the variables

-1r-9

Back to the equation:

-(-1r-9)



We calculate terms in parentheses: -(2(r+5)-4), so:

2(r+5)-4

We multiply parentheses

2r+10-4

We add all the numbers together, and all the variables

2r+6

Back to the equation:

-(2r+6)


We get rid of parentheses

3r+1r-2r+9-6+3=0

We add all the numbers together, and all the variables

2r+6=0

We move all terms containing r to the left, all other terms to the right

2r=-6

r=-6/2

r=-3