3(r+1)-2(3-2r)-3(3-r))=2(r+5)-4

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Solution for 3(r+1)-2(3-2r)-3(3-r))=2(r+5)-4 equation: 



3(r+1)-2(3-2r)-3(3-r))=2(r+5)-4

We move all terms to the left:

3(r+1)-2(3-2r)-3(3-r))-(2(r+5)-4)=0

We add all the numbers together, and all the variables

3(r+1)-2(-2r+3)-3(-1r+3))-(2(r+5)-4)=0

We add all the numbers together, and all the variables

3(r+1)-2(-2r+3)-3(-1r+3))-(2(r+5)=0

We multiply parentheses

3r+4r-3(-1r+3))-(2(r+5)+3-6=0

We add all the numbers together, and all the variables

7r-3(-1r+3))-(2(r+5)-3=0

We move all terms containing r to the left, all other terms to the right

7r-3(-1r+3))-(2(r+5)=3

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