3(r+1)=-2(2+r)

Solution for 3(r+1)=-2(2+r) equation:

3(r+1)=-2(2+r)

We move all terms to the left:

3(r+1)-(-2(2+r))=0

We add all the numbers together, and all the variables

3(r+1)-(-2(r+2))=0

We multiply parentheses

3r-(-2(r+2))+3=0


We calculate terms in parentheses: -(-2(r+2)), so:

-2(r+2)

We multiply parentheses

-2r-4

Back to the equation:

-(-2r-4)


We get rid of parentheses

3r+2r+4+3=0

We add all the numbers together, and all the variables

5r+7=0

We move all terms containing r to the left, all other terms to the right

5r=-7

r=-7/5

r=-1+2/5