3(r+1)=2(r+5)-4

Solution for 3(r+1)=2(r+5)-4 equation:

Simplifying
3(r + 1) = 2(r + 5) + -4

Reorder the terms:
3(1 + r) = 2(r + 5) + -4
(1 * 3 + r * 3) = 2(r + 5) + -4
(3 + 3r) = 2(r + 5) + -4

Reorder the terms:
3 + 3r = 2(5 + r) + -4
3 + 3r = (5 * 2 + r * 2) + -4
3 + 3r = (10 + 2r) + -4

Reorder the terms:
3 + 3r = 10 + -4 + 2r

Combine like terms: 10 + -4 = 6
3 + 3r = 6 + 2r

Solving
3 + 3r = 6 + 2r

Solving for variable 'r'.

Move all terms containing r to the left, all other terms to the right.

Add '-2r' to each side of the equation.
3 + 3r + -2r = 6 + 2r + -2r

Combine like terms: 3r + -2r = 1r
3 + 1r = 6 + 2r + -2r

Combine like terms: 2r + -2r = 0
3 + 1r = 6 + 0
3 + 1r = 6

Add '-3' to each side of the equation.
3 + -3 + 1r = 6 + -3

Combine like terms: 3 + -3 = 0
0 + 1r = 6 + -3
1r = 6 + -3

Combine like terms: 6 + -3 = 3
1r = 3

Divide each side by '1'.
r = 3

Simplifying
r = 3