3(r+12)=8-4r

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Solution for 3(r+12)=8-4r equation: 



3(r+12)=8-4r

We move all terms to the left:

3(r+12)-(8-4r)=0

We add all the numbers together, and all the variables

3(r+12)-(-4r+8)=0

We multiply parentheses

3r-(-4r+8)+36=0

We get rid of parentheses

3r+4r-8+36=0

We add all the numbers together, and all the variables

7r+28=0

We move all terms containing r to the left, all other terms to the right

7r=-28

r=-28/7

r=-4

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