3(r+2)+12-5(r-2)=

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Solution for 3(r+2)+12-5(r-2)= equation:


Simplifying
3(r + 2) + 12 + -5(r + -2) = 0

Reorder the terms:
3(2 + r) + 12 + -5(r + -2) = 0
(2 * 3 + r * 3) + 12 + -5(r + -2) = 0
(6 + 3r) + 12 + -5(r + -2) = 0

Reorder the terms:
6 + 3r + 12 + -5(-2 + r) = 0
6 + 3r + 12 + (-2 * -5 + r * -5) = 0
6 + 3r + 12 + (10 + -5r) = 0

Reorder the terms:
6 + 12 + 10 + 3r + -5r = 0

Combine like terms: 6 + 12 = 18
18 + 10 + 3r + -5r = 0

Combine like terms: 18 + 10 = 28
28 + 3r + -5r = 0

Combine like terms: 3r + -5r = -2r
28 + -2r = 0

Solving
28 + -2r = 0

Solving for variable 'r'.

Move all terms containing r to the left, all other terms to the right.

Add '-28' to each side of the equation.
28 + -28 + -2r = 0 + -28

Combine like terms: 28 + -28 = 0
0 + -2r = 0 + -28
-2r = 0 + -28

Combine like terms: 0 + -28 = -28
-2r = -28

Divide each side by '-2'.
r = 14

Simplifying
r = 14

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