3(r+2)+2r=-2r-64

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Solution for 3(r+2)+2r=-2r-64 equation: 



3(r+2)+2r=-2r-64

We move all terms to the left:

3(r+2)+2r-(-2r-64)=0

We add all the numbers together, and all the variables

2r+3(r+2)-(-2r-64)=0

We multiply parentheses

2r+3r-(-2r-64)+6=0

We get rid of parentheses

2r+3r+2r+64+6=0

We add all the numbers together, and all the variables

7r+70=0

We move all terms containing r to the left, all other terms to the right

7r=-70

r=-70/7

r=-10

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