3(r+2)-14=5(r-2)

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Solution for 3(r+2)-14=5(r-2) equation: 


Simplifying
3(r + 2) + -14 = 5(r + -2)

Reorder the terms:
3(2 + r) + -14 = 5(r + -2)
(2 * 3 + r * 3) + -14 = 5(r + -2)
(6 + 3r) + -14 = 5(r + -2)

Reorder the terms:
6 + -14 + 3r = 5(r + -2)

Combine like terms: 6 + -14 = -8
-8 + 3r = 5(r + -2)

Reorder the terms:
-8 + 3r = 5(-2 + r)
-8 + 3r = (-2 * 5 + r * 5)
-8 + 3r = (-10 + 5r)

Solving
-8 + 3r = -10 + 5r

Solving for variable 'r'.

Move all terms containing r to the left, all other terms to the right.

Add '-5r' to each side of the equation.
-8 + 3r + -5r = -10 + 5r + -5r

Combine like terms: 3r + -5r = -2r
-8 + -2r = -10 + 5r + -5r

Combine like terms: 5r + -5r = 0
-8 + -2r = -10 + 0
-8 + -2r = -10

Add '8' to each side of the equation.
-8 + 8 + -2r = -10 + 8

Combine like terms: -8 + 8 = 0
0 + -2r = -10 + 8
-2r = -10 + 8

Combine like terms: -10 + 8 = -2
-2r = -2

Divide each side by '-2'.
r = 1

Simplifying
r = 1

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