3(r+2)-5(2r-4)=0

Solution for 3(r+2)-5(2r-4)=0 equation:

Simplifying
3(r + 2) + -5(2r + -4) = 0

Reorder the terms:
3(2 + r) + -5(2r + -4) = 0
(2 * 3 + r * 3) + -5(2r + -4) = 0
(6 + 3r) + -5(2r + -4) = 0

Reorder the terms:
6 + 3r + -5(-4 + 2r) = 0
6 + 3r + (-4 * -5 + 2r * -5) = 0
6 + 3r + (20 + -10r) = 0

Reorder the terms:
6 + 20 + 3r + -10r = 0

Combine like terms: 6 + 20 = 26
26 + 3r + -10r = 0

Combine like terms: 3r + -10r = -7r
26 + -7r = 0

Solving
26 + -7r = 0

Solving for variable 'r'.

Move all terms containing r to the left, all other terms to the right.

Add '-26' to each side of the equation.
26 + -26 + -7r = 0 + -26

Combine like terms: 26 + -26 = 0
0 + -7r = 0 + -26
-7r = 0 + -26

Combine like terms: 0 + -26 = -26
-7r = -26

Divide each side by '-7'.
r = 3.714285714

Simplifying
r = 3.714285714