3(r+2)-5(4-r)+2=12

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Solution for 3(r+2)-5(4-r)+2=12 equation:


Simplifying
3(r + 2) + -5(4 + -1r) + 2 = 12

Reorder the terms:
3(2 + r) + -5(4 + -1r) + 2 = 12
(2 * 3 + r * 3) + -5(4 + -1r) + 2 = 12
(6 + 3r) + -5(4 + -1r) + 2 = 12
6 + 3r + (4 * -5 + -1r * -5) + 2 = 12
6 + 3r + (-20 + 5r) + 2 = 12

Reorder the terms:
6 + -20 + 2 + 3r + 5r = 12

Combine like terms: 6 + -20 = -14
-14 + 2 + 3r + 5r = 12

Combine like terms: -14 + 2 = -12
-12 + 3r + 5r = 12

Combine like terms: 3r + 5r = 8r
-12 + 8r = 12

Solving
-12 + 8r = 12

Solving for variable 'r'.

Move all terms containing r to the left, all other terms to the right.

Add '12' to each side of the equation.
-12 + 12 + 8r = 12 + 12

Combine like terms: -12 + 12 = 0
0 + 8r = 12 + 12
8r = 12 + 12

Combine like terms: 12 + 12 = 24
8r = 24

Divide each side by '8'.
r = 3

Simplifying
r = 3

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