3(r+2)=-5-2(r-3)

Solution for 3(r+2)=-5-2(r-3) equation:

3(r+2)=-5-2(r-3)

We move all terms to the left:

3(r+2)-(-5-2(r-3))=0

We multiply parentheses

3r-(-5-2(r-3))+6=0


We calculate terms in parentheses: -(-5-2(r-3)), so:

-5-2(r-3)

determiningTheFunctionDomain
-2(r-3)-5

We multiply parentheses

-2r+6-5

We add all the numbers together, and all the variables

-2r+1

Back to the equation:

-(-2r+1)


We get rid of parentheses

3r+2r-1+6=0

We add all the numbers together, and all the variables

5r+5=0

We move all terms containing r to the left, all other terms to the right

5r=-5

r=-5/5

r=-1