3(r+2)=25-16r

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Solution for 3(r+2)=25-16r equation: 



3(r+2)=25-16r

We move all terms to the left:

3(r+2)-(25-16r)=0

We add all the numbers together, and all the variables

3(r+2)-(-16r+25)=0

We multiply parentheses

3r-(-16r+25)+6=0

We get rid of parentheses

3r+16r-25+6=0

We add all the numbers together, and all the variables

19r-19=0

We move all terms containing r to the left, all other terms to the right

19r=19

r=19/19

r=1

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