3(r+2)=33-6r

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Solution for 3(r+2)=33-6r equation: 



3(r+2)=33-6r

We move all terms to the left:

3(r+2)-(33-6r)=0

We add all the numbers together, and all the variables

3(r+2)-(-6r+33)=0

We multiply parentheses

3r-(-6r+33)+6=0

We get rid of parentheses

3r+6r-33+6=0

We add all the numbers together, and all the variables

9r-27=0

We move all terms containing r to the left, all other terms to the right

9r=27

r=27/9

r=3

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