3(r+2)=7(r-2)

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Solution for 3(r+2)=7(r-2) equation: 



3(r+2)=7(r-2)

We move all terms to the left:

3(r+2)-(7(r-2))=0

We multiply parentheses

3r-(7(r-2))+6=0



We calculate terms in parentheses: -(7(r-2)), so:

7(r-2)

We multiply parentheses

7r-14

Back to the equation:

-(7r-14)



We get rid of parentheses

3r-7r+14+6=0

We add all the numbers together, and all the variables

-4r+20=0

We move all terms containing r to the left, all other terms to the right

-4r=-20

r=-20/-4

r=+5

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