3(r+20)=1/5(20r+400)

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Solution for 3(r+20)=1/5(20r+400) equation: 



3(r+20)=1/5(20r+400)

We move all terms to the left:

3(r+20)-(1/5(20r+400))=0



Domain of the equation: 5(20r+400))!=0

r∈R



We multiply parentheses

3r-(1/5(20r+400))+60=0

We multiply all the terms by the denominator


3r*5(20r+400))-(1+60*5(20r+400))=0

Wy multiply elements

15r^2(2+300r(2=0

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