3(r+3)=13+4r

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Solution for 3(r+3)=13+4r equation: 



3(r+3)=13+4r

We move all terms to the left:

3(r+3)-(13+4r)=0

We add all the numbers together, and all the variables

3(r+3)-(4r+13)=0

We multiply parentheses

3r-(4r+13)+9=0

We get rid of parentheses

3r-4r-13+9=0

We add all the numbers together, and all the variables

-1r-4=0

We move all terms containing r to the left, all other terms to the right

-r=4

r=4/-1

r=-4

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